问题背景：
我想通过google或者其他网站通过精准搜索确认该产品是否存在，但是即使该产品不存在google也会返回一些相关的url链接，现在想通过python实现搜索结果的精准匹配以确认该产品是否为正确的名称【可以通过google搜索到，如果搜索不到则认为该产品不存在】，以下为精准结果截图
实现代码：
import requests
from bs4 import beautifulsoup
def is_product(product):
query = product.replace(' ', ' ')
query = '"' query '"'
add = '&sca_esv=396701017a0fe9d3&sca_upv=1&sxsrf=adlywikwgdkr0hofoscsrshq3fr-z5vdma:1715482705794&ei=utbazqcxmmvk1e8pw_c8gak&ved=0ahukewjgg7ckj4egaxvlzfuhhum4d5aq4dudcbe&uact=5&oq="新能源汽车电池"&gs_lp=egxnd3mtd2l6lxnlcnaifylmlrdog73mupdmsb3ovabnllxmsaaimgyqabgega8ybhaagb4ydzigeaayhhgpmggqabiabbiibdiieaaygaqyogqycbaagiaegkiesp8fuabyahaaeacqaqcyaeiboahiaaobazitmbgba8gbapgbavgbazgcaaac5qgyawcsbwmyltggb8kc&sclient=gws-wiz-serp'
url = f"https://www.google.com/search?q={query}&as_q={query}&tbs=li:1"
print(url)
headers = {
"user-agent": "mozilla/5.0 (windows nt 10.0; win64; x64) applewebkit/537.36 (khtml, like gecko) chrome/91.0.4472.124 safari/537.36"
}
resp = requests.get(url, headers=headers)
decoded_text = resp.text
# print(">>>" * 20)
# print(decoded_text)
# print(">>>" * 20)
results = []
if resp.status_code == 200:
soup = beautifulsoup(resp.content, "html.parser")
# print(soup)
for g in soup.find_all('div', class_='tf2cxc'):
title = g.find('h3').text
link = g.find('a')['href']
item = {
"title": title,
"link": link
}
results.append(item)
print(results)
else:
print("failed to fetch search results")
return true if len(results)>=1 else false
query = '"新能源汽车电池"'
query = '"高档数控机床用变频智能电动执行器（电动夹爪）"'
query = '"cae—多学科设计集成与优化"'
res = []
for query in ["新能源汽车电池","高档数控机床用变频智能电动执行器（电动夹爪）","cae—多学科设计集成与优化"]:
res.append(is_product(query))
print(res)
